Tuesday, January 21, 2020
The Fencing Problem - Mathematics :: Math Coursework Mathematics
The Fencing Problem       Introduction     ============           I have been given 1000 meters of fencing and my aim is to find out the     maximum area inside.     ======================================================================         Prediction     ----------       I would predict that the more sides the shape has, then possibly the     bigger the area it will have, although I have nothing to base this on,     it will be what I am about to investigate.       Shapes:       I am going to start with the rectangle, I think this is a good     starting block because I am able to vary the widths and lengths to see     which has the bigger area. If I discover that the rectangles with     equal sides i.e. square bring me the best result, then I will try to     direct my investigation into furthering that particular theory.         Rectangles     ----------       [IMAGE]             Area = 40 000 m2     ================       [IMAGE]             Area = 60 000 m2       [IMAGE]             Area = 62 500 m2       It appears that the square shape has a bigger area, I would possibly     say that this is because the square has two bigger numbers, which are     multiplied together to give a greater number than when a big number is     multiplied with a smaller number.       However, I cannot take this for granted and I think using one more     shape will be useful in order to back up my theory.       [IMAGE]       Area = 52 500m       This proves my theory regarding squares and I shall now put my results     into a graph to show what I have found.       Length (m) Width (m) Area (m)       400 100 40 000       300 200 60 000       250 250 62 500       150 350 52 500       I will now further my investigation by looking at shapes of a     different nature:       [IMAGE]         Regular Pentagon     ----------------       The regular pentagon has 5 sides, and as we get 1000m of fencing, this     means each side will be 200m (1000Ã ¸5=200).      					    
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